Split list into number of Pieces

Today, while working with csv files i got into fantastic situation where i have a list of million values and i make iteration on that. So i thought, it would be easy for me if i split list into number of pieces which dont affect my code, memory and CPU. I can also use generator expression to make make my code run faster, but i was very curious to write code to split list into number of pieces(uses little of generator exp).
And the result is here -


    import os,sys

    def split_seq(seq, num_pieces):
        """ split a list into pieces passed as param """
        start = 0
        for i in xrange(num_pieces):
            stop = start + len(seq[i::num_pieces])
            yield seq[start:stop]
            start = stop

    seq = [i for i in range(100)]   ## define your list here
    num_of_pieces = 3
    for seq in split_seq(seq, num_of_pieces):
        print len(seq), '-> ',seq

Rename multiple file simultaneously

Renaming multiple file  once is really little confusing using command-line. There are lots of way to do it via programming, but yet, i didnt fine any on-the-spot command to do it.
So i used python to do it simply.
My requirement was actually:
1) i have one dedicated folder, where i have to rename all files.
2) all filename to be renamed are structured, i mean, i have to rename all dedupe_<number>.csv to <number>.csv

I did this using following code,

import os
from os import listdir, getcwd, rename


list_files = listdir(getcwd())
for filename in list_files:
    if not filename.startswith('.') and 'dedupe_' in filename:
        ext = filename.split('.')[-1]
        new_name = ''.join(filename.split('.')[:-1]).replace('dedupe_','')+'.'+ext
        cmd = 'mv '+filename + ' ' +new_name
        os.popen(cmd)

isn't it very very simple !!!!